按键平滑移动的代码方案。

Flash游戏教程 2007-4-12 12:30

在按键进行移动一个固定步长时，也可以在这个步长内，让移动的主体平滑的移动，这里的解决方案就是，开始移动时先去除掉键盘侦听，之后使用移动公式进行移动，移动结束后，恢复键盘侦听，接受下一次的键盘控制。

代码如下：

//基准步长, 单位: 30像素
var stepLength = 30;
//
//建立一个表示方向的全局变量
var dir:String;
//
//建立键盘侦听，接收键盘消息
var keyListener:Object = new Object();
keyListener.onKeyDown = function() {
if (Key.getCode() == Key.UP) {
  dir = "Up";
} else if (Key.getCode() == Key.RIGHT) {
  dir = "Right";
} else if (Key.getCode() == Key.DOWN) {
  dir = "Down";
} else if (Key.getCode() == Key.LEFT) {
  dir = "Left";
}
moveBox();
};
Key.addListener(keyListener);
//
//根据键盘消息进行单个箱子的位置移动
function moveBox() {
Key.removeListener(keyListener);
var temp = stepLength;
var short = 3; //平滑移动的最小单位，
switch (dir) {
case "Up" :
  onEnterFrame = function () {
   if (temp - short > 0) {
    box_mc._y -= short;
    temp -= short;
   } else {
    box_mc._y -= temp;
    Key.addListener(keyListener);
    delete this.onEnterFrame;
   }
  };
  break;
case "Right" :
  onEnterFrame = function () {
   if (temp - short > 0) {
    box_mc._x += short;
    temp -= short;
   } else {
    box_mc._x += temp;
    Key.addListener(keyListener);
    delete this.onEnterFrame;
   }
  };
  break;
case "Down" :
  onEnterFrame = function () {
   if (temp - short > 0) {
    box_mc._y += short;
    temp -= short;
   } else {
    box_mc._y += temp;
    Key.addListener(keyListener);
    delete this.onEnterFrame;
   }
  };
  break;
case "Left" :
  onEnterFrame = function () {
   if (temp - short > 0) {
    box_mc._x -= short;
    temp -= short;
   } else {
    box_mc._x -= temp;
    Key.addListener(keyListener);
    delete this.onEnterFrame;
   }
  };
  break;
default :
  trace("something wrong here!");
}
}