Let a closed path C pass N times around a current
(i.e., N is the winding number of the path around the current). Then the line integral of the magnetic field B along the path is given in cgs by

where c is the speed of light and
is the differential length element. Similarly, in MKS,

where
is the permeability of free space.


(1)
where c is the speed of light and


(2)
where

回复Comments
{commenttime}{commentauthor}
{CommentUrl}
{commentcontent}