The general field consisting of superimposed electric and magnetic fields is called an electromagnetic field. While properties such as the potential energy stored in the field remain invariant of the observing reference frame, special relativity shows that different observers will actually see differing strength of the constituent electric and magnetic fields. The electric and magnetic components of an electromagnetic field are untitled in special relativity into an entity known as the electromagnetic field tensor.
The potential energy of an electromagnetic field consisting of an electric field E and a magnetic field B in cgs is

and in MKS,

where
is the permittivity of free space and
is the permeability of free space.
For a particle in an electromagnetic field, the motion is circular.


Let
in (4)

and differentiate both sides

Plugging in (3) now gives

so the solution is

where

Integrating gives

We can now apply the initial conditions


so (10) becomes

Similarly, let
in (3)

and differentiate both sides

Plugging in (4) now gives

so the solution is

Integrating gives

We can now apply the initial conditions


so (18) becomes

However, (18) and (21) must also satisfy (3)

so

Therefore E = 0 and

Plugging these in to (13) and (21) give






But manipulating (25) and (26) gives


so the particle travels in a circle centered at
with radius 
If the electric and magnetic fields are at right angles, the path is a cycloid (Jeffreys and Jeffreys 1988).
The potential energy of an electromagnetic field consisting of an electric field E and a magnetic field B in cgs is

(1)
and in MKS,

(2)
where


For a particle in an electromagnetic field, the motion is circular.

(3)

(4)
Let


(5)
and differentiate both sides

(6)
Plugging in (3) now gives

(7)
so the solution is

(8)
where

(9)
Integrating gives

(10)
We can now apply the initial conditions

(11)

(12)
so (10) becomes

(13)
Similarly, let


(14)
and differentiate both sides

(15)
Plugging in (4) now gives

(16)
so the solution is

(17)
Integrating gives

(18)
We can now apply the initial conditions

(19)

(20)
so (18) becomes

(21)
However, (18) and (21) must also satisfy (3)

(22)
so

(23)
Therefore E = 0 and

(24)
Plugging these in to (13) and (21) give



(25)



(26)
But manipulating (25) and (26) gives


(27)
so the particle travels in a circle centered at


If the electric and magnetic fields are at right angles, the path is a cycloid (Jeffreys and Jeffreys 1988).
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