As in the case of the Schwarzschild solution for empty space with an isotropic static gravitational field, the case of a static gravitating spherical body of constant density can also be found exactly, as was first done by Schwarzschild (1916).Let M be the total mass, R the radius,
the density,
the mass inside radius r,P the pressure,and
the gravitational potential, then
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For a spherically symmetric metric,
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With
constant,
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and (6) becomes
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Integrating,
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Expanding the denominator of the left side,
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Using the integral
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(for q < 0) with
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so the indefinite integral of the left side is
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and the left side of (9) becomes
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Use the integral
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with
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so solve the right side of (9),
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Equating (15) and (19) gives
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Solving for P,
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Using
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and solving
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For spherical symmetry, the metric coefficients are then
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(Weinberg 1972, p. 331).
According to (24),
when
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which is unphysical, so it must be the case that
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(1)
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(2)
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(3)
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(4)
For a spherically symmetric metric,

(5)
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(6)
With
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(7)
and (6) becomes
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(8)
Integrating,

(9)
Expanding the denominator of the left side,

(10)
Using the integral
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(11)
(for q < 0) with
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(12)
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(13)
so the indefinite integral of the left side is
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(14)
and the left side of (9) becomes
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(15)
Use the integral
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(16)
with
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
(17)
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(18)
so solve the right side of (9),



(19)
Equating (15) and (19) gives
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(20)

(21)
Solving for P,

(22)
Using

(23)
and solving

(24)
For spherical symmetry, the metric coefficients are then
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(25)
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(26)
(Weinberg 1972, p. 331).
According to (24),


(27)

(28)
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(29)
which is unphysical, so it must be the case that

(30)
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